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BCNN(20;75;342)=?
BCNN (20;75;342)
tìm BCNN(20;75;342)
ƯCLN(60;165;315)=
BCNN(20;75;342)=
BCNN(20;75;342)
Ai trả lời nhanh đúng mình like cho
Biet rang : BCNN(a,b).UCLN(a,b)
a, BCNN cua hai so la 600, UCLN cua chung nho hon 10 lan BCNN. So thu 1 la 120, tim so thu 2.
b, UCLN cua hai so la 12, BCNN cua chung lon gap 6 lan UCLN . So t 1 la 24, tim so t 2
c, Tong cua hai so bang 60, tong giua UCLN va BCNN cua chung la 84. Tim hai so do.
BCNN cua (a,b)=100 vay BCNN (3a,7b) = ?
Tich cua 2 so biet UCLN cua chung = 5 & BCNN cua chung =30
biet rang BCNN(a,b).UCLN(a,b)=a.b
a, tong cua hai so bang 60,tong giua UCLN va BCNN cua chung la 84 tim hai so do
