Question

Bài1 : tính

a) \(\left(3x+\frac{5}{2}y\right)^2\);b)\(\left(x^2-\frac{3}{2}\right)^2\)

c) \(\frac{1}{4}-16x^2y^2\) ;d)\(\left(\frac{1}{5}x-2y\right)\left(2y+\frac{1}{5}x\right)\)

 

 

Answer 1

\(a,\left(3x+\frac{5}{2}y\right)^2=6x^2+15xy+6,25\)

\(b,\left(x^2-\frac{3}{2}\right)^2=x^2-3x+2,25\)

\(c,\frac{1}{4}-16x^2y^2=\frac{1}{2}^2-2x^2y^2=\left(\frac{1}{2}-2x^2y^2\right)\left(\frac{1}{2}+2x^2y^2\right)\)

\(d,\left(\frac{1}{5}x-2y\right)\left(2y+\frac{1}{5}x\right)=\left(\frac{1}{5}x-2y\right)\left(\frac{1}{5}x+2y\right)=......\)

bạn tự làm tiếp  nha

nếu sai thì cho mk xl nha