Question

bài 8: a, 3^2 x 1/243 x 81^2 x 1/3^3

b, (4.2^5) : (2^3 x 1/16)

Answer 1

\(8;a,3^2.\frac{1}{243}.81^2.\frac{1}{3^3}\)

\(=\frac{3^2.\left(3^4\right)^2}{243.3^3}\)

\(=\frac{3^2.3^8}{3^5.3^3}\)

\(=\frac{3^{10}}{3^8}=3^2=9\)

\(b,\frac{4.2^5}{2^3.\frac{1}{16}}\)

\(=\frac{2^2.2^5}{2^3.\frac{1}{2^4}}\)

\(=\frac{2^7}{\frac{1}{2}}=2^7.2=2^8\)

Answer 2

a, \(3^2.\frac{1}{243}.81^2.\frac{1}{3}^3\)

\(=3^2.\frac{1}{243}.\left(3^4\right)^2.\frac{1}{27}\)

\(=3^2.\frac{1}{243}.3^8.\frac{1}{27}\)

\(=\frac{3^2.3^8}{243.27}\)

\(=\frac{3^2.3^8}{3^5.3^3}\)

\(=\frac{3^{10}}{3^8}=3^2=9\)

b, \(\left(4.2^5\right):\left(2^3.\frac{1}{16}\right)\)

\(=\left(2^2.2^5\right):\left(8.\frac{1}{16}\right)\)

\(=2^7:\frac{1}{2}\)

\(=2^8\)