Question

Bài 5:Tính

A=\(1\frac{1}{3}.1\frac{1}{8}.1\frac{1}{15}.1\frac{1}{24}.1\frac{1}{35}\cdot...\cdot1\frac{1}{9800}\)

Mấy số trên là hỗn số đó

Answer 1

\(A=\frac{4}{3}.\frac{9}{8}.\frac{16}{15}.\frac{25}{24}.\frac{36}{35}......\frac{9801}{9800}=\frac{\left(2.3.4.5....99\right)^2}{1.3.2.4.3.5.4.6.....98.100}=\frac{2.3.4.5...99}{1.2.3.4.....98}.\frac{2.3.4.5....99}{3.4.5.6......100}=\frac{99}{1}.\frac{2}{100}=\frac{99}{50}\)

Answer 2

A=4/3.9/8.16/15.25/24. ... .9801/9800

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