Question

bài 4 gấp ạ

Answer 1

Câu 4:

\(1.m_{1.nguyên.tử.nhôm}=27.1,6605.10^{-24}=44,8335.10^{-24}\left(g\right)\\ 2.n_{Al}=\dfrac{5,4}{27}=0,2\left(mol\right)\\ Số.nguyên.tử.nhôm:0,2.6.10^{23}=1,2.10^{23}\left(nguyên.tử\right)\\ 3.NTK_X=\dfrac{8,6346.10^{-23}}{0,16605.10^{-23}}=52\left(\dfrac{g}{mol}\right)\\ \Rightarrow X:Crom\left(KHHH:Cr\right)\)