Question

bài 2 thôi ạ

Answer 1

a) \(n_{CaO}=\dfrac{5,6}{56}=0,1\left(mol\right)\)

PTHH: CaO + H₂O ---> Ca(OH)₂ 

            0,1---------------->0,1

            Ca(OH)₂ + 2HCl ---> CaCl₂ + 2H₂O

             0,1-------->0,2

=> \(C_{M\left(Ca\left(OH\right)_2\right)}=\dfrac{0,1}{0,5}=0,2M\)

b) \(m_{ddHCl}=\dfrac{0,2.36,5}{3,65\%}=200\left(g\right)\)