bài 1 :
a) 2/5 x 25/29 + 3/5 x 25/29
= (2/5 + 3/5) x 25/29
= 1 x 25/29
= 25/29
b) 5/2 x 3/7 - 3/14 : 6/7
= 15/14 - 1/4
= 23/28
c) 15/4 : 5/12 - 6/5 :11/15
= 9 - 18/11
= 81/11
`2/5 xx 25/29 + 3/5 xx 25/29`
` = 25/29 xx ( 2/5 + 3/5)`
`=25/29 xxx 5/5`
`= 25/29 xx1`
`= 25/29`
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`5/2 xx 3/7 - 3/14 : 6/7`
` = 5/2 xx 3/7 - 3/14 xx 7/6`
` = (5xx3)/(2xx7) - (3xx7)/(14xx6)`
` = 15/14 - 1/4`
`= 23/28`
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`15/4 : 5/12 - 6/5 : 11/15`
`= 15/4 xx 12/5 - 6/5 xx 15/11`
` = (15xx12)/(4xx5) - ( 6xx15)/(5xx11)`
`=9 - 18/11`
` = 99/11 - 18/11`
`= 81/11`
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`2/3 xx 20/21 xx 3/2 xx 7/5`
` = (2xx20xx3xx7)/(3xx21xx2xx5)`
` = 840/630`
`= 4/3`
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`5/17 xx 21/32 xx 47/24 xx 0`
` = 0`
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`11/3 xx 26/7 - 26/7 xx 8/3`
` = ( 11/3 - 8/3) xx 26/7`
`= 3/3 xx 26/7`
`= 1 xx 26/7`
`= 26/7`
bài 2 :
a) 2/3 x 20/21 x 3/2 x 7/5
= 40/63 x 3/2 x 7/5
= 20/21 x 7/5
= 4/3
b) 5/17 x 21/32 x 47/24 x 0
= (5/17 x 21/32 x 47/24) x 0
= 0
c) 11/3 x 26/7 - 267 x 8/3
= (11/3 - 8/3) x 26/7
= 1 x 26/7
= 26/7
\(1.a\)\(\dfrac{2}{5}\times\dfrac{25}{29}+\dfrac{3}{5}\times\dfrac{29}{25}\)
\(=\dfrac{25}{29}+\left(\dfrac{2}{5}+\dfrac{3}{5}\right)=\dfrac{25}{29}+\dfrac{1}{1}\)
\(\dfrac{25}{29}+\dfrac{29}{29}=\dfrac{54}{29}\)
\(b.\dfrac{5}{2}\times\dfrac{3}{7}-\dfrac{3}{14}:\dfrac{6}{7}\)
\(=\dfrac{15}{14}-\dfrac{21}{84}=\dfrac{30}{84}-\dfrac{21}{84}=\dfrac{9}{84}\)
\(c.\dfrac{15}{4}:\dfrac{5}{12}-\dfrac{6}{5}:\dfrac{11}{15}\)
\(=\dfrac{180}{48}-\dfrac{90}{55}=\dfrac{9900}{2640}-\dfrac{4320}{2640}=\dfrac{5580}{2640}=\dfrac{279}{132}=\dfrac{93}{44}\)
\(2.a.\dfrac{2}{3}\times\dfrac{20}{21}\times\dfrac{3}{2}\times\dfrac{7}{5}\)
\(\dfrac{40}{63}\times\dfrac{3}{2}\times\dfrac{7}{5}=\dfrac{120}{126}\times\dfrac{7}{5}=\dfrac{840}{630}=\dfrac{28}{21}\)
\(b.\dfrac{5}{17}\times\dfrac{21}{32}\times\dfrac{47}{24}\times0\)
\(=\dfrac{105}{544}\times\dfrac{47}{24}\times0=\dfrac{4935}{13056}\times0=0\)
\(c.\dfrac{11}{3}\times\dfrac{26}{7}-\dfrac{26}{7}\times\dfrac{8}{3}\)
\(=\dfrac{26}{7}\times\left(\dfrac{11}{3}-\dfrac{8}{3}\right)=\dfrac{26}{7}\times\dfrac{3}{3}=\dfrac{78}{21}=\dfrac{26}{7}\)