Question

Bài 1

1/24.25+1/25.26+...+1/29.30+y:1/3=-4

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Answer 1

\(\frac{1}{24.25}+\frac{1}{25.26}+\frac{1}{26.27}+...+\frac{1}{29.30}+y:\frac{1}{3}=-4\)

\(\frac{1}{24}-\frac{1}{25}+\frac{1}{25}-\frac{1}{26}+\frac{1}{26}-\frac{1}{27}+...+\frac{1}{29}-\frac{1}{30}+y:\frac{1}{3}=-4\)

\(\frac{1}{24}-\frac{1}{30}+3y=-4\)

\(\frac{1}{120}+3y=-4\)

\(3y=-4-\frac{1}{120}\)

\(3y=-\frac{481}{120}\)

\(y=-\frac{481}{120}:3\)

\(y=-\frac{481}{360}\)