Question

BÀI 1 : TÍNH

\(\dfrac{4}{9}+\dfrac{6}{9}+\dfrac{7}{9}\)

\(\dfrac{1}{2}\times\dfrac{2}{3}:\dfrac{1}{2}\)

\(\dfrac{2}{3}:\dfrac{2}{3}\times1\)

Answer 1

`4/9 + 6/9 + 7/9`

`= (4+6+7)/9`

`= 17/9`

`--------`

`1/2 xx 2/3 : 1/2`

`= 1/2 xx 2/3 xx 2`

`= 2/6 xx 2`

`= 4/6=2/3`

`--------`

`2/3 : 2/3 xx 1`

`= 2/3 xx 3/2 xx 1`

`= 1 xx 1=1`

 

Answer 2

\(a,=\dfrac{4+6+7}{9}=\dfrac{17}{9}\)

\(b,=\dfrac{1}{3}:\dfrac{1}{2}=\dfrac{2}{3}\)

\(c,=1\times1=1\)

Answer 3

\(\dfrac{4}{9}+\dfrac{6}{9}+\dfrac{7}{9}=\dfrac{17}{9}\)

\(\dfrac{1}{2}\times\dfrac{2}{3}:\dfrac{1}{2}=\dfrac{1}{2}\times\dfrac{2}{3}\times2=\dfrac{2}{3}\)

\(\dfrac{2}{3}:\dfrac{2}{3}\times1=\dfrac{2}{3}\times\dfrac{3}{2}\times1=\dfrac{6}{6}=1\)