Question

bài 1 tính  B = \(\frac{2^{12}.3^5-4^6.3^6}{2^{12}.9^3+8^4.3^5}\)

 

Answer 1

\(B=\frac{2^{12}.3^5-4^6.3^6}{2^{12}.9^3+8^4.3^5}=\frac{2^{12}.3^5-\left(2^2\right)^6.3^6}{2^{12}.\left(3^2\right)^3+\left(2^3\right)^4.3^5}=\frac{2^{12}.3^5-2^{12}.3^6}{2^{12}.3^6+2^{12}.3^5}=\frac{2^{12}.\left(3^5-3^6\right)}{2^{12}.\left(3^6+3^5\right)}=\frac{3^5-3^6}{3^6+3^5}=\frac{3^5.\left(1-3\right)}{3^5.\left(3+1\right)}=\frac{1-3}{3+1}=-\frac{2}{4}=-\frac{1}{2}\)