Question

Bài 1: Tính:          

A. 4/7 + 4

B.3 + 6/11

c.15/24 + 2

Answer 1

A=\(\dfrac{4+28}{7}=\dfrac{32}{7}\)

B=\(\dfrac{33+6}{11}=\dfrac{39}{11}\)

C=\(\dfrac{15+48}{24}=\dfrac{63}{24}=\dfrac{21}{8}\)

Answer 2

A=32/7

B=39/11

C=21/8