Question

Bài 1:   Tính              

 a) (2x – 3).(x + 2) – x.(x + 1)                                b) 5.(x² – y²) – (x – y).(x + y)

 c) 2.(1 – x²) + (3x + 1).(x - 2)                               d) 4x.(x + y) – (2x - y)²

 e)  2a(a+1)-(2a²-1)                                                f)  4(x+2)²+(3+2x)(3-2x)

 g)  (x³ - 3x² + x - 3):( x - 3)                         h)  (2x⁴ - 5x² + x³ – 3 - 3x):(x² - 3)

Answer 1

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Answer 2

\(a,=2x^2+x-6-x^2-x=x^2-6\\ b,=5x^2-5y^2-x^2+y^2=4x^2-4y^2\\ c,=2-2x^2+3x^2-6x+x-2=x^2-5x\\ d,=4x^2+4xy-4x^2+4xy-y^2=8xy-y^2\\ e,=2a^2+2a-2a^2+1=2a+1\\ f,=4x^2+16x+16+9-4x^2=16x+25\\ g,=\left[x^2\left(x-3\right)+\left(x-3\right)\right]:\left(x-3\right)=x^2+1\\ h,=\left(2x^4-6x^2+x^3-3x+x^2-3\right):\left(x^2-3\right)\\ =\left[2x^2\left(x^2-3\right)+x\left(x^2-3\right)+\left(x^2-3\right)\right]:\left(x^2-3\right)\\ =2x^2+x+1\)