Question

Bài 1: Tìm x

\(a.\dfrac{2}{3}+\dfrac{1}{3}:x=1\)

\(b.\dfrac{1}{3}+\dfrac{2}{3}.x=\dfrac{14}{15}\)

 

Answer 1

`2/3 +1/3 :x =1`

`1/3 :x = 1 -2/3 = 3/3 -2/3 =1/3`

`x = 1/3 :1/3 =1`

`1/3 + 2/3 *x = 14/15`

`2/3 *x = 14/15 -1/3 = 14/15 - 5/15`

`2/3 *x = 9/15 = 3/5`

`x = 3/5 : 2/3 = 9/10`

Answer 2

a) \(\dfrac{2}{3}+\dfrac{1}{3}:x=1\)

\(\dfrac{1}{3}:x=1-\dfrac{2}{3}=\dfrac{3}{3}-\dfrac{2}{3}\)

\(\dfrac{1}{3}:x=\dfrac{1}{3}\)

\(x=\dfrac{1}{3}:\dfrac{1}{3}\)

\(x=1\)

b) \(\dfrac{1}{3}+\dfrac{2}{3}\times x=\dfrac{14}{15}\)

\(\dfrac{2}{3}\times x=\dfrac{14}{15}-\dfrac{1}{3}=\dfrac{14}{15}-\dfrac{5}{15}\)

\(\dfrac{2}{3}\times x=\dfrac{9}{15}=\dfrac{3}{5}\)

\(x=\dfrac{3}{5}:\dfrac{2}{3}=\dfrac{3}{5}\times\dfrac{3}{2}\)

\(x=\dfrac{9}{10}\)