\(2x^2+3.\left(x^2-1\right)=5x.\left(x+1\right)\)
\(\Leftrightarrow2x^2+3x^2-3=5x^2+5x\)
\(\Leftrightarrow5x^2-5x^2-5x=3\)
\(\Leftrightarrow-5x=3\)
\(\Leftrightarrow x=-\frac{3}{5}\)
\(\text{Vậy }x=-\frac{3}{5}\)
Trả lời:
Bài 1:
a, 2x2 + 3 ( x2 - 1 ) = 5x ( x + 1 )
=> 2x2 + 3x2 - 3 = 5x2 + 5x
=> 5x2 - 3 = 5x2 + 5x
=> 5x2 - 3 - 5x2 - 5x = 0
=> - 3 - 5x = 0
=> - 5x = 3
=> x = - 3/5
Vậy x = - 3/5