\(2Mg+O_2\rightarrow2MgO\)
2x____x____________
\(4Ag+O_2\rightarrow2Ag_2O\)
4y____y__________
\(V_{O2}=\frac{11,2}{22,4}=0,5\left(mol\right)\)
Theo đề bài ta có hệ phương trình :
\(\left\{{}\begin{matrix}24x+108y=6,8\\2x+4y=0,5\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=\frac{67}{300}\\y=\frac{1}{75}\end{matrix}\right.\left(mol\right)\)
a,
\(m_{MgO}=2.\frac{67}{200}.\left(24+16\right)=17,87\left(g\right)\)
\(m_{Ag2O}=\frac{2}{75}.\left(216+16\right)=6,19\left(g\right)\)
\(\Rightarrow m=17,87+6,19=24,06\left(g\right)\)
b,
\(\%_{Ag2O}=\frac{6,19}{24,06}.100\%=25,73\%\)
\(\%_{MgO}=100\%-25,73\%=74,27\%\)