\(n_P=\dfrac{1,55}{31}=0,05mol\\ 4P+5O_2\xrightarrow[t^0]{}2P_2O_5\\ n_{P_2O_5}=\dfrac{0,05.2}{4}=0,025mol\)
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\(n_P=\dfrac{1,55}{31}=0,05mol\\ 4P+5O_2\xrightarrow[t^0]{}2P_2O_5\\ n_{P_2O_5}=\dfrac{0,05.2}{4}=0,025mol\)