Question

B = ( \(5\frac{1}{7}\) + \(\frac{19}{29}\) ) + ( \(7\frac{43}{52}\) + \(1\frac{10}{29}\) ) + \(\frac{9}{52}\)

Answer 1

NHẦM LÀM LẠI :

\(B=\left(5+7+1\right)+\left(\frac{19}{29}+\frac{10}{29}\right)+\left(\frac{43}{52}+\frac{9}{52}\right)+\frac{1}{7}=13+1+1+\frac{1}{7}=15\frac{1}{7}\)

Answer 2

B=\(\left(5+\frac{1}{7}+\frac{19}{29}\right)+\left(7+\frac{43}{52}+1+\frac{10}{29}\right)+\frac{9}{52}=\left(5+7+1\right)+\left(\frac{19}{29}+\frac{10}{29}\right)+\left(\frac{43}{52}+\frac{10}{52}+\frac{9}{52}\right)+\frac{1}{7}=13+1+1+\frac{1}{7}=15\frac{1}{7}\)