đk x > 9/4
\(A=\left(\dfrac{2\sqrt{x}-5\left(\sqrt{x}-1\right)}{\left(2\sqrt{x}-3\right)\left(\sqrt{x}-1\right)}\right):\left(\dfrac{3-3\sqrt{x}+2}{1-\sqrt{x}}\right)\)
\(=\dfrac{3\sqrt{x}-5}{\left(2\sqrt{x}-3\right)\left(\sqrt{x}-1\right)}.\dfrac{\sqrt{x}-1}{5-3\sqrt{x}}=\dfrac{1}{3-2\sqrt{x}}\)