Bài này dễ mà:
A=(100-1^2)(100-2^2)(100-3^2)...(100-10^2)...(100-25^2)
A=(100-1)(100-4)(100-9)...(100-100)...(100-625)
=> A=0
đến giữa dãy số có (100-10^2) đó =>A=0
Bài này dễ mà:
A=(100-1^2)(100-2^2)(100-3^2)...(100-10^2)...(100-25^2)
A=(100-1)(100-4)(100-9)...(100-100)...(100-625)
=> A=0
đến giữa dãy số có (100-10^2) đó =>A=0
\(M=\left(100-1\right).\left(100-2^2\right).\left(100-3^2\right).....\left(100-50^2\right)\)
Tính nhanh:
\(A=\left(100-1\right).\left(100-2^2\right).\left(100-3^2\right)....\left(100-50^2\right)\)
Tính :
\(\left[\frac{1}{100}-1^2\right].\left[\frac{1}{100}-\left(\frac{1}{2}\right)^2\right].\left[\frac{1}{100}-\left(\frac{1}{3}\right)^2\right]...\left[\frac{1}{100}-\left(\frac{1}{20}\right)^2\right]\)
Tính:
\(\left[\frac{1}{100}-1^2\right].\left[\frac{1}{100}-\left(\frac{1}{2}\right)^2\right].\left[\frac{1}{100}-\left(\frac{1}{3}\right)^2\right].....\left[\frac{1}{100}-\left(\frac{1}{20}\right)^2\right]\)
Tính:
\(\left[\frac{1}{100}-1^2\right].\left[\frac{1}{100}-\left(\frac{1}{2}\right)^2\right].\left[\frac{1}{100}-\left(\frac{1}{3}\right)^2\right].....\left[\frac{1}{100}-\left(\frac{1}{20}\right)^2\right]\)
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\(\left(\sqrt{100-1}\right).\left(\sqrt{100-2}\right).\left(\sqrt{100-3}\right)....\left(\sqrt{100-55}\right)\)
\(\left(1000-1^{ }3\right).\left(1000-2^{ }3\right).\left(1000-3^{ }3\right)....\left(1000-25^{ }3\right)\)
\(^{\left(-1\right)^2.\left(-1\right)^{ }3.\left(-1\right)^{ }4.......\left(-1\right)^{ }100}\)
\(A=\left(2+4+6+...+100\right)\left(\frac{3}{5}:0,7+3\left(\frac{-2}{7}\right)\right):\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+...+\frac{1}{100}\right)\)
tính A=\(\left[\frac{100}{2}\right]+\left[\frac{100}{2^2}\right]+...+\left[\frac{100}{2^6}\right]\)
B=\(\left[\sqrt{1}\right]+\left[\sqrt{2}\right]+...+\left[\sqrt{500}\right]\)
C=\(\left[\frac{-12}{3}\right]+\left[\frac{-11}{3}\right]+...+\left[\frac{12}{3}\right]\)