AI giúp tui
Bài 1:
\(Đặt:a=\dfrac{1}{x-1}\left(x\ne1\right);b=\sqrt{y}\left(y\ge0\right)\\ \left\{{}\begin{matrix}\dfrac{2}{x-1}+2\sqrt{y}=8\\\dfrac{11}{x-1}-3\sqrt{y}=2\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}2a+2b=8\\11a-3b=2\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}3a+3b=12\\11a-3b=2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}14a=14\\a+b=4\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}a=1\\b=3\end{matrix}\right.\\ Vậy:a=\dfrac{1}{x-1}=1\Leftrightarrow x=2\left(TM\right);b=\sqrt{y}=3\Leftrightarrow y=9\left(TM\right)\)
Vậy hpt có cặp nghiệm (x;y)= (2;9)
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