Dễ thấy 5=4+1=x+1
Thay vào C,ta có:
\(C=x^5-\left(x+1\right)x^4+\left(x+1\right)x^3-\left(x+1\right)x^2+\left(x+1\right)x-1\)
\(=x^5-x^5-x^4+x^4+x^3-x^3-x^2+x^2+x-1=x-1=4-1=3\)
TINH GIA TRI BIEU THUC:
A=X^5 + 5X^4 - 5X^3 - 5X^2 + 5X-1
Voi X = 4
rut gon bieu thuc M=1/x - 2/(5-x) - x+5/(x^2-5x) voi x khac 0 ; x khac 5
cho bieu thuc : M ( x phan x^2 -25 - x-5 phan x^2 +5x ) : 2x-5 phan 5x - x^2
a) rut gon M
b) tinh gia tri cua M voi x = -2010
c) tim tat ca cac gia tri nguyen cua x de M co gia tri nguyen.
Giup em voi a
Giai cac bat phuong trinh sau va bieu dien tap nghiem cua bat phuong trinh tren truc so:
a. 2(3x-1)-2x<2x-1
b. 4x-8≥3(3x-2)+4-2x
c. 3(x-2)(x+2)<3x²+x
d. (x+4)(5x-1)>5x²+16x+2
rut gon bieu thuc :P=5x(x-3)(x+3)-(2x-3)^2+34x(x+2)-5(x+2)^3+25x-1
1) Tinh gia tri bieu thuc:
C= \(\frac{5x^2+3y^2}{10x^2-3y^2}\)voi \(\frac{x}{3}=\frac{y}{5}\)
rut gon bieu thuc a,(3x+2)^2+4x-3^2+2(5x-2)(5x+2)-75x^2
b,(x-2)^3+(2x+1)^3++2(x+2)(1-x)-9x^3+2x
Rut gon phan thuc: (x^(3)-x^(2)-x-2)/(x^(5)-3x^(4)+4x^(3)-5x^(2)+3x-2)
Minh that su da bo tay vs bai tap nay roi! Cac ban hay giup minh nhe! Minh xin cam on!
ai jup em lam phep tinh nay dc ko?A=x5-5x4+5x3-5x2+5x-1 tai x=4
rut gon trc thay so vao sau nhe