A = 0 nha bạn k cho mình nha bạn
\(\frac{\left|2x-3\right|+\left|6y-7\right|}{\left|6x-9\right|+\left|18y-21\right|}=\frac{\left|2x-3\right|+\left|6y-7\right|}{3\left(\left|2x-3\right|+\left|6y-7\right|\right)}=\frac{1}{3}\)
\(\frac{\left(x-2\right)^2+\left(2y-4\right)^2}{\left(3x-6\right)^2+\left(6y-12\right)^2}=\left(\frac{\left(x-2\right)+\left(2y-4\right)}{\left(3x-6\right)+\left(6y-12\right)}\right)^2=\left(\frac{\left(x-2\right)+\left(2y-4\right)}{3\left[\left(x-2\right)+\left(2y-4\right)\right]}\right)^2=\left(\frac{1}{3}\right)^2=\frac{1}{9}\)
A=1/3-1/9=2/9