Question

Ai giải đc mk tk nha:

Tìm x, y nguyên bt: \(\frac{1}{x}=\frac{1}{6}+\frac{3}{y}\)

Giumf nha 

 

Answer 1

\(\frac{1}{x}=\frac{1}{6}+\frac{3}{y}\) <=> \(\frac{1}{x}=\frac{y+18}{6y}\) (x, y khác 0)

=> \(x=\frac{6y}{y+18}=\frac{6y+108-108}{y+18}=\frac{6\left(y+18\right)-108}{y+18}\)

=> \(x=6-\frac{108}{y+18}\)

=> Để x nguyên thì 108 chia hết cho y+18 => y+18=(-2,-3,-4,-6,-9,-12,-27,-36,-54,-108,2,3,4,6,9,12,18,27,36,54,108)

=> y và x

Answer 2

\(\frac{1}{x}\)= \(\frac{1}{6}\)+\(\frac{3}{y}\)

        = 6+3 = 1+y

        = 9 =1+y

       y = 9-1

       y = 8

\(\frac{1}{x}\)= 8

x = 1.8

x = 8