Question

ai biết thì trả lời giùm mik nha

(x-3)^2-X^2=11

(5x-3)-25(x^2-4)=0

(6x-3)^2-36x(x-1)=40

(2-x)^2-7(x^2+11)=0

 

Answer 1

tìm x nha

Answer 2

+(x-3)²-x²=11

x²-6x+9-x²=11

-6x+9=11

-6x=2

x=2:-6

x=-1/3

(6x-3)²-36x(x-1)=40

36x²-36x+9-36x²+36x=40

9=40

=> đề sai

(2-x)²-7(x²+11)=0

4-4x+x²-7x²-77=0

-73-4x-6x²

ht bt