Ta có : A = \(\frac{2^{2014}+1}{2^{2014}}=1+\frac{1}{2^{2014}}\)
B = \(\frac{2^{2014}+2}{2^{2014}+1}=1+\frac{1}{2^{2014}+1}\)
Vì : \(\frac{1}{2^{2014}}>\frac{1}{2^{2014}+1}\)
Nên A > B
Được thôi ban :
Ta có : \(A=\frac{2^{2014}+1}{2^{2014}}=\frac{2^{2014}}{2^{2014}}+\frac{1}{2^{2014}}=1+\frac{1}{2^{2014}}\)
\(B=\frac{2^{2014}+2}{2^{2014}+1}=\frac{2^{2014}+1}{2^{2014}+1}+\frac{1}{2^{2014}+1}=1+\frac{1}{2^{2014}+1}\)
Đó ok chưa