Question

a)\(\frac{2^{15}.9^4}{6^6.8^3}\)

b)\(\frac{6^3+3.6^2+3^3}{-13}\)

Answer 1

\(a,\frac{2^{15}.9^4}{6^6.8^3}=\frac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^6.\left(2^3\right)^3}=\frac{2^{15}.3^8}{2^6.3^6.2^9}=\frac{2^{15}.3^8}{2^{15}.3^6}=3^2=9\)

\(b,\frac{6^3+3.6^2+3^3}{-13}=\frac{\left(3.2\right)^3+3.\left(3.2\right)^2+3^3}{-13}=\frac{3^3.2^3+3.3^2.2^2+3^3}{-13}\)

                                 \(=\frac{3^3.2^3+3^3.2^2+3^3}{-13}=\frac{3^3.\left(2^3+2^2+1\right)}{-13}=\frac{3^3.\left(8+4+1\right)}{-13}=\frac{3^3.13}{-13}=-3^8=\frac{1}{3^8}\)