\(\frac{1.1}{1.2}.\frac{2.2}{2.3}\frac{3.3}{3.4}...\frac{100.100}{100.101}\)
\(=\frac{\left(1.2.3...100\right).\left(1.2.3...100\right)}{\left(1.2.3...100\right).\left(2.3...101\right)}\)
\(=\frac{1}{1.101}\)
\(=\frac{1}{101}\)
k cho mk nha
\(\frac{1.1}{1.2}.\frac{2.2}{2.3}\frac{3.3}{3.4}...\frac{100.100}{100.101}\)
\(=\frac{\left(1.2.3...100\right).\left(1.2.3...100\right)}{\left(1.2.3...100\right).\left(2.3...101\right)}\)
\(=\frac{1}{1.101}\)
\(=\frac{1}{101}\)
k cho mk nha
\(\frac{1^2}{1.2}.\frac{2^2}{2.3}.\frac{3^2}{3.4}.....\frac{100^2}{100.101}\)
\(\frac{1^2}{1.2}.\frac{2^2}{2.3}.\frac{3^{^2}}{3.4}...\frac{99^2}{99.100}.\frac{100^2}{100.101}\)
Tính
\(\frac{1^2}{1.2}+\frac{2^2}{2.3}+\frac{3^2}{3.4}...\frac{100^2}{100.101}\)
Tính:
a) \(\frac{1^2}{1.2}.\frac{2^2}{2.3}.\frac{3^2}{3.4}...\frac{99^2}{99.100}.\frac{100^2}{100.101}\)
b)\(\frac{2^2}{1.3}.\frac{3^2}{2.4}.\frac{4^2}{3.5}...\frac{59^2}{58.60}\)
A = \(\frac{1^2}{^{1.2}}\). \(\frac{2^2}{2.3}\) . \(\frac{3^2}{3.4}\). . ... . \(\frac{100^2}{100.101}\)
\(\frac{1^2}{1.2}\) . \(\frac{^{2^2}}{2.3}\) . \(\frac{3^2}{3.4}\)................\(\frac{100^2}{100.101}\)
\(\frac{2}{1.2}+\frac{2}{2.3}+\frac{2}{3.4}+...+\frac{2}{100.101}=?\)
Tính giá trị biểu thức
\(\frac{1^2}{1.2}\). \(\frac{2^2}{2.3}\). \(\frac{3^2}{3.4}\)......... \(\frac{100^2}{100.101}\)
tính
a) \(\frac{1^2}{1.2}\).\(\frac{2^2}{2.3}\).\(\frac{3^2}{3.4}\).....\(\frac{99^2}{99.100}\).\(\frac{100^2}{100.101}\)
b) \(\frac{2^2}{1.3}\).\(\frac{3^2}{2.4}\).\(\frac{4^2}{3.5}\).....\(\frac{59^2}{58.60}\)