-(-a+b+c)+(b+c-1)=(b-c+6)-(7-a-b)+c
a-b-c+b+c-1=b-c+6-7+b+c
a-1=2c-1
a=2c
Ta có :
- ( -a + b + c ) + ( b + c -1 )
= a - b - c + b + c - 1
= ( b - b ) + ( c - c ) + a - 1
= 0 + 0 + a -1
= a - 1
Ta có :
( b - c + 6 ) - ( 7 - a + b ) + c
= b - c + 6 - 7 + a - b + c
= 0 + 0 + a - 1
= a - 1
Vì a - 1 = a - 1
=> - ( a + b + c ) + ( b + c - 1 ) = ( b - c + 6 ) - ( 7 - a + b ) + c ( đpcm )