\(abab+ab=2550\)
\(\Rightarrow ab\times101+ab\times1=2550\)
\(\Rightarrow ab\times\left(101+1\right)=2550\)
\(\Rightarrow ab\times102=2550\)
\(\Rightarrow ab=2550:102\)
\(\Rightarrow ab=25\)
Vậy \(ab=25\)
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Ta có :
abab + ab = 2550
ab x 101 + ab x 1 = 2550
ab x ( 101 + 1 ) = 2550
ab x 102 = 2550
ab = 2550 : 102
=> ab = 25
Ta có : \(\overline{abab}+\overline{ab}=2550\)
\(\Rightarrow\overline{ab00}+\overline{ab}+\overline{ab}=2550\)
\(\Rightarrow\overline{ab}\times101+\overline{ab}=2550\)
\(\Rightarrow\overline{ab}\times\left(101+1\right)=2550\)
\(\Rightarrow\overline{ab}\times102=2550\)
\(\overline{ab}=2550:102\)
\(\overline{ab}=25\)
Vậy \(\overline{ab}\)=25.