\(4\dfrac{3}{8}+5\dfrac{2}{3}=\dfrac{4\times8+3}{8}+\dfrac{5\times3+2}{3}\\ =\dfrac{35}{8}+\dfrac{17}{3}=\dfrac{35\times3+17\times8}{24}=\dfrac{241}{24}\\ ----\\ 2\dfrac{3}{8}+1\dfrac{1}{4}=\dfrac{2\times8+3}{8}+\dfrac{1\times4+1}{4}=\dfrac{19}{8}+\dfrac{5}{4}\\ =\dfrac{19+5\times2}{8}=\dfrac{29}{8}\\ ----\\ 2\dfrac{3}{8}-1\dfrac{1}{4}+5\dfrac{1}{3}=\left(2-1+5\right)+\left(\dfrac{3}{8}-\dfrac{1}{4}+\dfrac{1}{3}\right)\\ =6+\dfrac{3\times3-1\times6+1\times8}{24}\\ =6+\dfrac{11}{24}=6\dfrac{11}{24}\)
a, 35/8 + 17/3
= 241/24
b, 19/8 + 5/4 + 27/7
= 29/8 + 27/7
= 419/56
c, 19/8 - 5/4 + 27/7
= 9/8 + 27/7
= 279/56.
a,4\(\dfrac{3}{8}\)+5\(\dfrac{2}{3}\)=(4+5)+(\(\dfrac{3}{8}\)+\(\dfrac{2}{3}\))=9+\(\dfrac{25}{24}\)=\(\dfrac{241}{24}\)
b,2\(\dfrac{3}{8}\)+1\(\dfrac{1}{4}\)+3\(\dfrac{6}{7}\)=(2+1+3)+(\(\dfrac{3}{8}\)+\(\dfrac{1}{4}\)+\(\dfrac{6}{7}\))=6+\(\dfrac{83}{56}\)=\(\dfrac{419}{56}\)
c,2\(\dfrac{3}{8}\)-1\(\dfrac{1}{4}\)+5\(\dfrac{1}{3}\)=(2-1+5)+(\(\dfrac{3}{8}\)-\(\dfrac{1}{4}\)+\(\dfrac{1}{3}\))=6+\(\dfrac{11}{24}\)=\(\dfrac{155}{24}\).
