\(A=\dfrac{3}{4\cdot5}+\dfrac{3}{5\cdot6}+...+\dfrac{3}{59\cdot60}\\ =3\left(\dfrac{1}{4\cdot5}+\dfrac{1}{5\cdot6}+...+\dfrac{1}{59\cdot60}\right)\\ =3\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+...+\dfrac{1}{59}-\dfrac{1}{60}\right)\\ =3\left(\dfrac{1}{4}-\dfrac{1}{60}\right)=3\left(\dfrac{15}{60}-\dfrac{1}{60}\right)\\ =3\cdot\dfrac{7}{30}=\dfrac{7}{10}\)