Question

\(a,2.\left(x-\dfrac{1}{2}\right)-5.\left(x+\dfrac{3}{5}\right)=-x+\dfrac{1}{3}\)

\(b,x\left(x-\dfrac{1}{3}\right)-\dfrac{1}{2}x\left(2x-3\right)=\dfrac{1}{4}\)

Answer 1

`a) 2(x-1/2) -5(x+3/5) = -x+1/3`

`<=> 2x - 1 - 5x - 3 = 1/3 -x`

`<=> -3x -4 - 1/3 +x =0`

`<=> -2x - 13/3 =0`

`<=> -2x =13/3  => x = 13/3 : (-2) = -13/6`

`b)x(x-1/3) - 1/2 x (2x-3) =1/4`

`<=> x^2 - 1/3x - x^2 + 3/2x - 1/4 =0`

`<=> -7/6x - 1/4 = 0`

`<=> -7/6x = 1/4`

`<=> x = 1/4 : (-7/6) = -3/14`

Answer 2

a. 2x - 1 - (5x + 3) = -x + 1/3

<=> 2x - 1 - 5x - 3 = -x + 1/3

<=> -3x - 4 = -x + 1/3

<=> -4 - 1/3 = -x + 3x

<=> -13/3 = 2x

<=> x = -13/3 : 2 = -13/6

Vậy ...

b. x² - 1/3x - x² - 3/2x = 1/4

<=> -7/6x = 1/4

<=> x = 1/4 : (-7/6)

<=> x = -3/14