a, \(\dfrac{21x^2\left(y+1\right)^3}{24x^3\left(1+y\right)^2}=\dfrac{21x^2\left(y+1\right)^3}{24x^3\left(y+1\right)^2}=\dfrac{7\left(y+1\right)}{8x}\)
b, Xem lại đề
c, \(\dfrac{5\left(x-y\right)-3\left(y-x\right)}{10\left(x-y\right)}=\dfrac{5\left(x-y\right)+3\left(x-y\right)}{10\left(x-y\right)}=\dfrac{8\left(x-y\right)}{10\left(x-y\right)}=\dfrac{4}{5}\)
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a, 21x2(y+1)324x3(1+y)2=21x2(y+1)324x3(y+1)2=7(y+1)8x21x2(y+1)324x3(1+y)2=21x2(y+1)324x3(y+1)2=7(y+1)8x
b, Hình như bạn bị sai đề rồi
c, 5(x−y)−3(y−x)10(x−y)=5(x−y)+3(x−y)10(x−y)=8(x−y)10(x−y)=455(x−y)−3(y−x)10(x−y)=5(x−y)+3(x−y)10(x−y)=8(x−y)10(x−y)=45
❤Học tốt nhé bạn❤
✔ cho mình nhé❤
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