\(A=\left(\dfrac{1}{2}-\dfrac{1}{3}\right).\left(\dfrac{1}{2}-\dfrac{1}{5}\right).\left(\dfrac{1}{2}-\dfrac{1}{7}\right)...\left(\dfrac{1}{2}-\dfrac{1}{99}\right)\)
\(=\dfrac{1}{2.3}.\dfrac{3}{2.5}.\dfrac{5}{2.7}...\dfrac{97}{2.99}=\dfrac{1.3.5.7...97}{2^{49}.3.5.7...99}\) (Có 49 thừa số)
\(=\dfrac{1}{2^{49}.99}\)