Tuyển Cộng tác viên Hoc24 nhiệm kì 26 tại đây: https://forms.gle/dK3zGK3LHFrgvTkJ6
Các câu hỏi tương tự
tính :
C=(112/13.20+112/20.27+112/27.34+...+112/62.69):(-5/9.13-7/9.25-13/19.25-31/19.69)
Tính hợp lí : (112/13.20+112/20.27+...+112/62.69):(-5/9.13-7/9.25-13/19.25-31/19.69)
\(\left(\frac{112}{13.20}+\frac{112}{20.27}+\frac{112}{27.34}+....+\frac{112}{62.69}\right):\left(-\frac{5}{9.13}-\frac{7}{9.25}-\frac{13}{19.25}-\frac{31}{19.69}\right)\)
A =( \(\frac{112}{13.20}+\frac{112}{20.27}+\frac{112}{27.34}+...\frac{112}{62.69}\)): ( \(\frac{-5}{9.13}-\frac{-7}{9.25}-\frac{13}{19.25}-\frac{31}{19.69}\)) = ?
\(\left(\frac{112}{13.20}+\frac{112}{20.27}+\frac{112}{27.34}+...+\frac{112}{62.69}\right)\) \(:\left(-\frac{5}{9.13}-\frac{7}{9.25}-\frac{13}{19.25}-\frac{31}{19.69}\right)\)
Tính \(A=\left(\frac{112}{13.20}+\frac{112}{20.27}+...+\frac{112}{62.69}\right)\div\)\(\left(\frac{-5}{9.13}-\frac{7}{9.25}-\frac{13}{19.25}-\frac{31}{19.69}\right)\)
A = (\(\frac{112}{13.20}+\frac{112}{20.27}+\frac{112}{27.34}+...+\frac{112}{62.69}\)) : \(\frac{-5}{9.13}-\frac{-7}{9.25}+\frac{-13}{19.25}+\frac{-31}{19.69}\))
Cố gắng giúp mik với nhé
Tính
\(E=\left(\frac{112}{13.20}+\frac{112}{20.27}+...+\frac{112}{62.69}\right):\left(-\frac{5}{9.3}-\frac{7}{9.25}-\frac{13}{19.25}-\frac{31}{19.69}\right)\)
Tính
(\(\frac{112}{13.20}+\frac{112}{20.27}+\frac{112}{27.34}+...+\frac{112}{62.64}\))
: (\(\frac{-5}{9.13}-\frac{7}{9.25}-\frac{13}{19.25}-\frac{31}{19.69}\)