Question

a) Tính tổng A = 1/5 + 1/10 + 1/20 + 1/40 + ... + 1/1280

b) Tìm số tự nhiên n : 121/27.54/11 < n < 100/21 : 25/126

Answer 1

a) \(A=\frac{1}{5}+\frac{1}{10}+\frac{1}{20}+\frac{1}{40}+...+\frac{1}{1280}\)

\(A.2=\frac{2}{5}+\frac{1}{5}+\frac{1}{10}+\frac{1}{20}+\frac{1}{40}+...+\frac{1}{640}\)

\(A.2-A=\left(\frac{2}{5}+\frac{1}{5}+\frac{1}{10}+\frac{1}{20}+\frac{1}{40}+...+\frac{1}{640}\right)-\left(\frac{1}{5}+\frac{1}{10}+\frac{1}{20}+\frac{1}{40}+...+\frac{1}{1280}\right)\)

\(A=\frac{2}{5}-\frac{1}{1280}=\frac{511}{1280}\)

b) \(\frac{121}{27}.\frac{54}{11}< n< \frac{100}{21}:\frac{25}{126}\)

\(22< n< 24\)

=>  n = 23