Question

 

a, Tìm abc biết : abc + 1133 = abc8

b, tìm abc biết abc nhân 9 = 3abc 

 

Answer 1

a,     abc=125

b,     abc=375

Answer 2

a)tach abc thanh abc+8

b)abc x 9=3abc

=>abc x 9=3000+abc

=>abc x9 -abc =3000

=>abc x (9-1)=3000

=>abx x8=3000

=>abc=3000:8

=>abc=375

Answer 3

a. abc + 1133 = abc8

=> abc + 1133 = 10 x abc + 8

=> 1133 - 8 = 10 x abc - abc

=> 1125 = 9 x abc

=> abc = 1125 : 9

Vậy abc = 125.

b. abc x 9 = 3abc

=> abc x 9 = 3000 + abc

=> abc x 9 - abc = 3000

=> abc x 8 = 3000

=> abc = 3000 : 8

Vậy abc = 375.

Answer 4

a,

abc + 1133 = abc8   hay  

abc + 1133 = abc x 10 + 8  

1133 = abc x 9 + 8  

abc x 9 = 1133 – 8 =1125  

abc = 1125 : 9  

abc = 125

b,

abc x 9 =3abc   =>  abc x 8 + abc = 3000 + abc  

abc x 8 = 3000  =>     abc = 3000 : 8  

abc = 375