HL
11 tháng 4 2022 lúc 13:53
Các câu hỏi tương tự
KJ
28 tháng 1 2022 lúc 22:23
\(l,\dfrac{\dfrac{3}{41}-\dfrac{12}{47}+\dfrac{27}{53}}{\dfrac{4}{41}-\dfrac{16}{47}+\dfrac{36}{53}}\)
\(m,\left(3-2\dfrac{1}{3}+\dfrac{1}{4}\right):\left(4-5\dfrac{1}{6}+2\dfrac{1}{4}\right)\)
\(n,F=\dfrac{4}{2.4}+\dfrac{4}{4.6}+\dfrac{4}{6.8}+...+\dfrac{4}{2008.2010}\)
\(p,F=\dfrac{1}{18}+\dfrac{1}{54}+\dfrac{1}{108}+...+\dfrac{1}{990}\)
Tìm x biết:
a, \(\dfrac{3}{5}:x+\dfrac{1}{5}=\dfrac{11}{25}\)
b, \(2\left(x-\dfrac{1}{3}\right)-1\dfrac{2}{3}=\dfrac{-23}{15}\)
c, \(\left|x+1\right|-\dfrac{1}{7}=\dfrac{1}{3}\)
d, \(\dfrac{x+1}{3}=\dfrac{2x-1}{5}\)
Tìm x:
\(\dfrac{39}{41}-\dfrac{25}{x}=\dfrac{-47}{41}.\dfrac{16}{7}\)
Tìm sốtựnhiên x biết: \(\dfrac{1}{1.3}+\dfrac{1}{3.5}+\dfrac{1}{5.7}+....+\dfrac{1}{x.\left(x+2\right)}=\dfrac{20}{41}\)
a)dfrac{-3}{7}+dfrac{15}{26}-left(dfrac{2}{13}-dfrac{3}{7}right)b)2.dfrac{3}{7}+left(dfrac{2}{9}-1dfrac{3}{7}right)-dfrac{5}{3}:dfrac{1}{9}c)dfrac{-11}{23}.dfrac{6}{7}+dfrac{8}{7}.dfrac{-11}{23}-dfrac{1}{23}d)left(dfrac{377}{-231}-dfrac{123}{89}+dfrac{34}{791}right).left(dfrac{1}{6}-dfrac{1}{8}-dfrac{1}{24}right) nhanh lên giúp mình vs
Đọc tiếp
a)\(\dfrac{-3}{7}+\dfrac{15}{26}-\left(\dfrac{2}{13}-\dfrac{3}{7}\right)\)
b)\(2.\dfrac{3}{7}+\left(\dfrac{2}{9}-1\dfrac{3}{7}\right)-\dfrac{5}{3}:\dfrac{1}{9}\)
c)\(\dfrac{-11}{23}.\dfrac{6}{7}+\dfrac{8}{7}.\dfrac{-11}{23}-\dfrac{1}{23}\)
d)\(\left(\dfrac{377}{-231}-\dfrac{123}{89}+\dfrac{34}{791}\right).\left(\dfrac{1}{6}-\dfrac{1}{8}-\dfrac{1}{24}\right)\)
nhanh lên giúp mình vs
Tính:a) dfrac{-5}{9}+dfrac{8}{15}+dfrac{-2}{11}+dfrac{4}{-9}+dfrac{7}{15} b)left(dfrac{-5}{12}+dfrac{6}{11}right)+left(dfrac{7}{17}+dfrac{5}{11}+dfrac{5}{12}right)c) A 49dfrac{8}{23}-left(5dfrac{7}{32}+14dfrac{8}{23}right)d) C dfrac{-3}{7}.dfrac{5}{9}+dfrac{4}{9}.dfrac{-3}{7}+2dfrac{3}{7}
Đọc tiếp
Tính:
a) \(\dfrac{-5}{9}\)\(+\dfrac{8}{15}+\dfrac{-2}{11}+\dfrac{4}{-9}+\dfrac{7}{15}\)
b)\(\left(\dfrac{-5}{12}+\dfrac{6}{11}\right)+\left(\dfrac{7}{17}+\dfrac{5}{11}+\dfrac{5}{12}\right)\)
c) A= \(49\dfrac{8}{23}-\left(5\dfrac{7}{32}+14\dfrac{8}{23}\right)\)
d) C= \(\dfrac{-3}{7}.\dfrac{5}{9}+\dfrac{4}{9}.\dfrac{-3}{7}+2\dfrac{3}{7}\)
bài 1:tínha)left(dfrac{-7}{15}-dfrac{27}{70}right)-left(dfrac{8}{15}+dfrac{43}{70}right)b)dfrac{3}{7}+left(dfrac{-1}{5}+dfrac{-3}{7}right)c)left(4-dfrac{12}{5}right).dfrac{25}{8}-dfrac{2}{5}:dfrac{-4}{25}d)left(dfrac{-5}{24}+dfrac{3}{4}-dfrac{7}{12}right):left(-dfrac{5}{16}right)e)dfrac{-5}{7}.dfrac{2}{11}+dfrac{-5}{7}.dfrac{9}{11}g)dfrac{6}{7}+dfrac{5}{4}:left(-5right)-dfrac{-1}{28}.left(-2right)^2
Đọc tiếp
bài 1:tính
a)\(\left(\dfrac{-7}{15}-\dfrac{27}{70}\right)-\left(\dfrac{8}{15}+\dfrac{43}{70}\right)\)
b)\(\dfrac{3}{7}+\left(\dfrac{-1}{5}+\dfrac{-3}{7}\right)\)
c)\(\left(4-\dfrac{12}{5}\right).\dfrac{25}{8}-\dfrac{2}{5}:\dfrac{-4}{25}\)
d)\(\left(\dfrac{-5}{24}+\dfrac{3}{4}-\dfrac{7}{12}\right):\left(-\dfrac{5}{16}\right)\)
e)\(\dfrac{-5}{7}.\dfrac{2}{11}+\dfrac{-5}{7}.\dfrac{9}{11}\)
g)\(\dfrac{6}{7}+\dfrac{5}{4}:\left(-5\right)-\dfrac{-1}{28}.\left(-2\right)^2\)
H24
12 tháng 5 2022 lúc 20:43
\(\dfrac{99}{100}:\left(\dfrac{1}{4}-\dfrac{1}{12}+\dfrac{1}{3}\right)-\left(\dfrac{-7}{5}\right)^2\)
\(\dfrac{13}{15}\cdot0,25\cdot3+\left(\dfrac{8}{15}-1\dfrac{19}{60}\right):1\dfrac{23}{24}\)
1, dfrac{-5}{7} . dfrac{2}{11} + dfrac{-5}{7} . dfrac{9}{11} + 1dfrac{5}{7}
2,-3dfrac{4}{13} . 15dfrac{3}{41} + 3dfrac{4}{13} . 2dfrac{3}{41}
3, dfrac{4}{5} . 15dfrac{1}{4} - dfrac{4}{5} . 15dfrac{1}{3} + dfrac{11}{30}
4,dfrac{4}{20} + dfrac{16}{42} + dfrac{6}{15} - dfrac{3}{5} + dfrac{2}{21} - dfrac{10}{21} + dfrac{3}{10}
Giúp mik nha. Cảm ơn
Đọc tiếp
1, \(\dfrac{-5}{7}\) . \(\dfrac{2}{11}\) + \(\dfrac{-5}{7}\) . \(\dfrac{9}{11}\) + \(1\dfrac{5}{7}\)
2,\(-3\dfrac{4}{13}\) . \(15\dfrac{3}{41}\) + \(3\dfrac{4}{13}\) . \(2\dfrac{3}{41}\)
3, \(\dfrac{4}{5}\) . \(15\dfrac{1}{4}\) - \(\dfrac{4}{5}\) . \(15\dfrac{1}{3}\) + \(\dfrac{11}{30}\)
4,\(\dfrac{4}{20}\) + \(\dfrac{16}{42}\) + \(\dfrac{6}{15}\) - \(\dfrac{3}{5}\) + \(\dfrac{2}{21}\) - \(\dfrac{10}{21}\) + \(\dfrac{3}{10}\)
Giúp mik nha. Cảm ơn