Question

a, \(\dfrac{2x+3}{24}\) = \(\dfrac{3x-1}{32}\)

b, \(\dfrac{13x-2}{2x+5}\) = \(\dfrac{76}{17}\)

Đề bài là tìm x, mọi người giúp mình vs ạ

Answer 1

a) \(\dfrac{2x+3}{24}=\dfrac{3x-1}{32}\)

\(\Rightarrow32\left(2x+3\right)=24\left(3x-1\right)\)

\(\Rightarrow64x+96=72x-24\)

\(\Rightarrow8x=120\Rightarrow x=15\)

b) \(\dfrac{13x-2}{2x+5}=\dfrac{76}{17}\)

\(\Rightarrow17\left(13x-2\right)=76\left(2x+5\right)\)

\(\Rightarrow221x-34=152x+380\)

\(\Rightarrow69x=414\Rightarrow x=6\)