\(\frac{a}{5}=\frac{b}{8}=\frac{c}{3}\)và a - 2b + c = 34
Ta có:
\(\frac{a}{5}=\frac{b}{8}=\frac{c}{3}=\frac{a}{5}=\frac{2b}{16}=\frac{c}{3}\)
Áp dụng tính chất dãy tỉ số bằng nhau,, ta có:
\(\frac{a}{5}=\frac{2b}{16}=\frac{c}{3}=\frac{a-2b+c}{5-16+3}=\frac{34}{-8}=-\frac{17}{4}\)
\(\Rightarrow\frac{a}{5}=-\frac{17}{4}\Rightarrow a=-\frac{17}{4}.5=-\frac{85}{4}\)
\(\Rightarrow\frac{2b}{16}=-\frac{17}{4}\Rightarrow2b=-\frac{17}{4}.16=-68\Rightarrow b=68:2=34\)
\(\Rightarrow\frac{c}{3}=-\frac{17}{4}\Rightarrow c=-\frac{17}{4}.3=-\frac{51}{4}\)
Vậy a = .......
b = ...........
c = .............
\(\frac{a}{5}=\frac{b}{8}=\frac{c}{3}=\frac{a-2b+c}{5-2.8+3}=\frac{34}{-8}\)
=>a=\(\frac{34}{-8}.5=\frac{170}{-8}\)
b=\(\frac{34}{-8}.8=\frac{272}{-8}\)
c=\(\frac{34}{-8}.3=\frac{102}{-8}\)
1 k nhá
\(15a=10b=6c\Rightarrow\frac{a}{2}=\frac{b}{3}=\frac{c}{5}\)
Ta có:
Đặt:
\(\frac{a}{2}=\frac{b}{3}=\frac{c}{5}=k\)
\(\Rightarrow a=k.2\)
\(\Rightarrow b=k.3\)
\(\Rightarrow c=k.5\)
Thế vào a .b . c = -1920, ta có:
\(\Rightarrow\left(k.2\right).\left(k.3\right).\left(k.5\right)=-1920\)
\(\Rightarrow k^3.30=-1920\)
\(\Rightarrow k^3=\left(-1920\right):30\)
\(\Rightarrow k^3=-64\)
\(\Rightarrow k=-4\)
Tự thê vào tìm a , b , c nah bạn ~