Question

a) 4/x-2-x+2=0

b) x+1/x-2-x-1/x+2=2(x^2+2)/x^2-4

c) 2/x-3+x-5/x-1=2

Answer 1

a) 4/x-2-x+2=0a)\(\dfrac{4}{x-2}-x+2=0\)

ĐKXĐ: x khác 2

\(\Leftrightarrow\) \(\dfrac{4-x\cdot\left(x-2\right)+2\cdot\left(x-2\right)}{x-2}=0\)

\(\Leftrightarrow\) \(4-x^2+2x+2x-4=0\)

\(\Leftrightarrow\) \(x^2+4x=0\)

\(\Leftrightarrow\) x*(x+4) = 0

\(\Leftrightarrow\) \(\left[{}\begin{matrix}x=0\\x+4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\left(tm\right)\\x=-4\left(tm\right)\end{matrix}\right.\)

Vậy S = \(\left\{0;-4\right\}\)

b) \(\dfrac{x+1}{x-2}-\dfrac{x-1}{x+2}=\dfrac{2\cdot\left(x^2+2\right)}{x^2-4}\)

Answer 2

Bùn ngủ wa tớ sẽ giải đáp cho bạn trong ngày mai