a) \(\dfrac{3}{5}+x=\dfrac{4}{3}\)
\(\Leftrightarrow x=\dfrac{4}{3}-\dfrac{3}{5}\)
\(\Leftrightarrow x=\dfrac{20}{15}-\dfrac{9}{15}\)
\(\Leftrightarrow x=\dfrac{11}{15}\)
b) \(x+\dfrac{5}{6}=\dfrac{1}{7}\)
\(\Leftrightarrow x=\dfrac{1}{7}-\dfrac{5}{6}\)
\(\Leftrightarrow x=\dfrac{6}{42}-\dfrac{35}{42}\)
\(\Leftrightarrow x=-\dfrac{29}{42}\)
c) \(x\times\dfrac{3}{8}=\dfrac{3}{4}\)
\(\Leftrightarrow x=\dfrac{3}{4}:\dfrac{3}{8}\)
\(\Leftrightarrow x=\dfrac{3}{4}\times\dfrac{8}{3}\)
\(\Leftrightarrow x=2\)
d) \(\dfrac{4}{5}\times x=\dfrac{3}{7}\)
\(\Leftrightarrow x=\dfrac{3}{7}:\dfrac{4}{5}\)
\(\Leftrightarrow x=\dfrac{3}{7}\times\dfrac{5}{4}\)
\(\Leftrightarrow x=\dfrac{15}{28}\)
a, \(\dfrac{3}{5}+x=\dfrac{4}{3}\Leftrightarrow x=\dfrac{4}{3}-\dfrac{3}{5}=\dfrac{20-9}{15}=\dfrac{11}{15}\)
b, \(x+\dfrac{5}{6}=\dfrac{1}{7}\Leftrightarrow x=\dfrac{1}{7}-\dfrac{5}{6}=\dfrac{6-35}{42}=\dfrac{-29}{42}\)
c, \(\dfrac{3x}{8}=\dfrac{3}{4}\Leftrightarrow\dfrac{3x}{8}=\dfrac{6}{8}\Rightarrow3x=6\Leftrightarrow x=2\)
d, \(\dfrac{4x}{5}=\dfrac{3}{7}\Leftrightarrow\dfrac{28x}{35}=\dfrac{15}{35}\Rightarrow x=\dfrac{15}{28}\)
a, \(\dfrac{3}{5}\) + \(X\) = \(\dfrac{4}{3}\)
\(X\) = \(\dfrac{4}{3}\) - \(\dfrac{3}{5}\)
\(X\) = \(\dfrac{11}{15}\)
b, \(X\) + \(\dfrac{5}{6}\) = \(\dfrac{1}{7}\)
\(X\) = \(\dfrac{1}{7}\) - \(\dfrac{5}{6}\)
\(X\) = -\(\dfrac{29}{42}\)
c, \(X\) x \(\dfrac{3}{8}\) = \(\dfrac{3}{4}\)
\(X\) = \(\dfrac{3}{4}\) : \(\dfrac{3}{8}\)
\(X\) = 2
d, \(\dfrac{4}{5}\) x \(X\) = \(\dfrac{3}{7}\)
\(X\) = \(\dfrac{3}{7}\) : \(\dfrac{4}{5}\)
\(X\) = \(\dfrac{15}{28}\)
#Yu