Question

A= 2 mũ 0+2 mũ 1+2 mũ 2+2 mũ 3+...+2 mũ 2010. Tính tổng

Answer 1

\(A=2^0+2^1+2^2+...+2^{2010}\)

\(2A=2^1+2^2+2^3+...+2^{2021}\)

\(2A-A=\left(2^1+2^2+2^3+...+2^{2021}\right)-\left(2^0+2^1+2^2+...+2^{2020}\right)\)

\(A=2^{2021}-1\)