Question

a) 11+6\(\sqrt{2}\) = \(\left(3+\sqrt{2}\right)^2\)

b) 8-2\(\sqrt{7}\)=\(\left(\sqrt{7}-1\right)^2\)

c)\(\sqrt{11+6\sqrt{2}}=\sqrt{11-6\sqrt{2}}=6\)

d) \(\sqrt{8-2\sqrt{7}}-\sqrt{8+2\sqrt{7}}=-2\)

Answer 1

Bn ghi đề vào nhé .