\(A=1+\dfrac{1}{3}+\dfrac{1}{9}+\dfrac{1}{27}+\dfrac{1}{81}\) \(\Rightarrow3A=3+1+\dfrac{1}{3}+\dfrac{1}{9}+\dfrac{1}{27}\)
\(\Rightarrow3A-A=3-\dfrac{1}{81}\Rightarrow2A=\dfrac{242}{81}\Rightarrow A=\dfrac{121}{81}\)
=1+(27/81+9/81+3/81+1/81)
=1+40/81
=81/81+40/81
=121/81