\(9\left(3x-2\right)=x\left(2-3x\right)\)
\(\Rightarrow9\left(3x-2\right)-x\left(2-3x\right)=0\)
\(\Rightarrow\left(3x-2\right)\left(9+x\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{2}{3}\\x=-9\end{matrix}\right.\)
9(3x-2)=x(2-3x)
9(3x-2)-x(2-3x)=0
9(3x-2)+x(3x-2)=0
(3x-2)(9+x)=0
=>TH1:3x-2=0;x=3/2
=>TH2:9+x=0;x=-9