Question

9.(-1/3)^3+1/6√4

Answer 1

0

Answer 2

\(9.\left(-\dfrac{1}{3}\right)^3+\dfrac{1}{6}\sqrt{4}\\ =9.\left(-\dfrac{1}{27}\right)+\dfrac{1}{6}.2\\ =\dfrac{-1}{3}+\dfrac{1}{3}\\ =0\)