\(\dfrac{8}{9}\times\dfrac{1}{2}+\dfrac{10}{9}\times\dfrac{1}{2}=\dfrac{1}{2}\left(\dfrac{8}{9}+\dfrac{10}{9}\right)=\dfrac{1}{2}\times\dfrac{18}{9}=\dfrac{1}{2}\times2=1\)
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