Question

8-x/(x+2)(x-3)+2/x+2

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Answer 1

\(\frac{8-x}{\left(x+2\right)\left(x-3\right)}+\frac{2}{x+2}=\frac{8-x+2\left(x-3\right)}{\left(x+2\right)\left(x-3\right)}\)\(=\frac{8-x+2x-6}{\left(x+2\right)\left(x-3\right)}=\frac{2+x}{\left(x+2\right)\left(x-3\right)}=\frac{x+2}{\left(x+2\right)\left(x-3\right)}=\frac{1}{x-3}\)