Ta có: \(\left|\dfrac{7}{8}x+\dfrac{5}{6}\right|-\left|\dfrac{1}{2}x+5\right|=0\)
\(\Rightarrow\left[{}\begin{matrix}\dfrac{7}{8}x+\dfrac{5}{6}=0\\\dfrac{1}{2}x+5=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}\dfrac{7}{8}x=-\dfrac{5}{6}\\\dfrac{1}{2}x=-5\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-\dfrac{20}{21}\\x=-10\end{matrix}\right.\)
Vậy \(\left[{}\begin{matrix}x=-\dfrac{20}{21}\\x=-10\end{matrix}\right.\)